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authorPaul E. McKenney <paulmck@linux.vnet.ibm.com>2014-03-01 01:11:28 +0100
committerPaul E. McKenney <paulmck@linux.vnet.ibm.com>2014-04-29 17:38:33 +0200
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tree2831f1d9bf2c3523081312b4d0a5d45eaf19c6a8 /Documentation/RCU/rcu_dereference.txt
parentdocumentation: Update sysfs path for rcu_cpu_stall_suppress (diff)
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documentation: Record rcu_dereference() value mishandling
Recent LKML discussings (see http://lwn.net/Articles/586838/ and http://lwn.net/Articles/588300/ for the LWN writeups) brought out some ways of misusing the return value from rcu_dereference() that are not necessarily completely intuitive. This commit therefore documents what can and cannot safely be done with these values. Signed-off-by: Paul E. McKenney <paulmck@linux.vnet.ibm.com> Reviewed-by: Josh Triplett <josh@joshtriplett.org>
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+PROPER CARE AND FEEDING OF RETURN VALUES FROM rcu_dereference()
+
+Most of the time, you can use values from rcu_dereference() or one of
+the similar primitives without worries. Dereferencing (prefix "*"),
+field selection ("->"), assignment ("="), address-of ("&"), addition and
+subtraction of constants, and casts all work quite naturally and safely.
+
+It is nevertheless possible to get into trouble with other operations.
+Follow these rules to keep your RCU code working properly:
+
+o You must use one of the rcu_dereference() family of primitives
+ to load an RCU-protected pointer, otherwise CONFIG_PROVE_RCU
+ will complain. Worse yet, your code can see random memory-corruption
+ bugs due to games that compilers and DEC Alpha can play.
+ Without one of the rcu_dereference() primitives, compilers
+ can reload the value, and won't your code have fun with two
+ different values for a single pointer! Without rcu_dereference(),
+ DEC Alpha can load a pointer, dereference that pointer, and
+ return data preceding initialization that preceded the store of
+ the pointer.
+
+ In addition, the volatile cast in rcu_dereference() prevents the
+ compiler from deducing the resulting pointer value. Please see
+ the section entitled "EXAMPLE WHERE THE COMPILER KNOWS TOO MUCH"
+ for an example where the compiler can in fact deduce the exact
+ value of the pointer, and thus cause misordering.
+
+o Do not use single-element RCU-protected arrays. The compiler
+ is within its right to assume that the value of an index into
+ such an array must necessarily evaluate to zero. The compiler
+ could then substitute the constant zero for the computation, so
+ that the array index no longer depended on the value returned
+ by rcu_dereference(). If the array index no longer depends
+ on rcu_dereference(), then both the compiler and the CPU
+ are within their rights to order the array access before the
+ rcu_dereference(), which can cause the array access to return
+ garbage.
+
+o Avoid cancellation when using the "+" and "-" infix arithmetic
+ operators. For example, for a given variable "x", avoid
+ "(x-x)". There are similar arithmetic pitfalls from other
+ arithmetic operatiors, such as "(x*0)", "(x/(x+1))" or "(x%1)".
+ The compiler is within its rights to substitute zero for all of
+ these expressions, so that subsequent accesses no longer depend
+ on the rcu_dereference(), again possibly resulting in bugs due
+ to misordering.
+
+ Of course, if "p" is a pointer from rcu_dereference(), and "a"
+ and "b" are integers that happen to be equal, the expression
+ "p+a-b" is safe because its value still necessarily depends on
+ the rcu_dereference(), thus maintaining proper ordering.
+
+o Avoid all-zero operands to the bitwise "&" operator, and
+ similarly avoid all-ones operands to the bitwise "|" operator.
+ If the compiler is able to deduce the value of such operands,
+ it is within its rights to substitute the corresponding constant
+ for the bitwise operation. Once again, this causes subsequent
+ accesses to no longer depend on the rcu_dereference(), causing
+ bugs due to misordering.
+
+ Please note that single-bit operands to bitwise "&" can also
+ be dangerous. At this point, the compiler knows that the
+ resulting value can only take on one of two possible values.
+ Therefore, a very small amount of additional information will
+ allow the compiler to deduce the exact value, which again can
+ result in misordering.
+
+o If you are using RCU to protect JITed functions, so that the
+ "()" function-invocation operator is applied to a value obtained
+ (directly or indirectly) from rcu_dereference(), you may need to
+ interact directly with the hardware to flush instruction caches.
+ This issue arises on some systems when a newly JITed function is
+ using the same memory that was used by an earlier JITed function.
+
+o Do not use the results from the boolean "&&" and "||" when
+ dereferencing. For example, the following (rather improbable)
+ code is buggy:
+
+ int a[2];
+ int index;
+ int force_zero_index = 1;
+
+ ...
+
+ r1 = rcu_dereference(i1)
+ r2 = a[r1 && force_zero_index]; /* BUGGY!!! */
+
+ The reason this is buggy is that "&&" and "||" are often compiled
+ using branches. While weak-memory machines such as ARM or PowerPC
+ do order stores after such branches, they can speculate loads,
+ which can result in misordering bugs.
+
+o Do not use the results from relational operators ("==", "!=",
+ ">", ">=", "<", or "<=") when dereferencing. For example,
+ the following (quite strange) code is buggy:
+
+ int a[2];
+ int index;
+ int flip_index = 0;
+
+ ...
+
+ r1 = rcu_dereference(i1)
+ r2 = a[r1 != flip_index]; /* BUGGY!!! */
+
+ As before, the reason this is buggy is that relational operators
+ are often compiled using branches. And as before, although
+ weak-memory machines such as ARM or PowerPC do order stores
+ after such branches, but can speculate loads, which can again
+ result in misordering bugs.
+
+o Be very careful about comparing pointers obtained from
+ rcu_dereference() against non-NULL values. As Linus Torvalds
+ explained, if the two pointers are equal, the compiler could
+ substitute the pointer you are comparing against for the pointer
+ obtained from rcu_dereference(). For example:
+
+ p = rcu_dereference(gp);
+ if (p == &default_struct)
+ do_default(p->a);
+
+ Because the compiler now knows that the value of "p" is exactly
+ the address of the variable "default_struct", it is free to
+ transform this code into the following:
+
+ p = rcu_dereference(gp);
+ if (p == &default_struct)
+ do_default(default_struct.a);
+
+ On ARM and Power hardware, the load from "default_struct.a"
+ can now be speculated, such that it might happen before the
+ rcu_dereference(). This could result in bugs due to misordering.
+
+ However, comparisons are OK in the following cases:
+
+ o The comparison was against the NULL pointer. If the
+ compiler knows that the pointer is NULL, you had better
+ not be dereferencing it anyway. If the comparison is
+ non-equal, the compiler is none the wiser. Therefore,
+ it is safe to compare pointers from rcu_dereference()
+ against NULL pointers.
+
+ o The pointer is never dereferenced after being compared.
+ Since there are no subsequent dereferences, the compiler
+ cannot use anything it learned from the comparison
+ to reorder the non-existent subsequent dereferences.
+ This sort of comparison occurs frequently when scanning
+ RCU-protected circular linked lists.
+
+ o The comparison is against a pointer that references memory
+ that was initialized "a long time ago." The reason
+ this is safe is that even if misordering occurs, the
+ misordering will not affect the accesses that follow
+ the comparison. So exactly how long ago is "a long
+ time ago"? Here are some possibilities:
+
+ o Compile time.
+
+ o Boot time.
+
+ o Module-init time for module code.
+
+ o Prior to kthread creation for kthread code.
+
+ o During some prior acquisition of the lock that
+ we now hold.
+
+ o Before mod_timer() time for a timer handler.
+
+ There are many other possibilities involving the Linux
+ kernel's wide array of primitives that cause code to
+ be invoked at a later time.
+
+ o The pointer being compared against also came from
+ rcu_dereference(). In this case, both pointers depend
+ on one rcu_dereference() or another, so you get proper
+ ordering either way.
+
+ That said, this situation can make certain RCU usage
+ bugs more likely to happen. Which can be a good thing,
+ at least if they happen during testing. An example
+ of such an RCU usage bug is shown in the section titled
+ "EXAMPLE OF AMPLIFIED RCU-USAGE BUG".
+
+ o All of the accesses following the comparison are stores,
+ so that a control dependency preserves the needed ordering.
+ That said, it is easy to get control dependencies wrong.
+ Please see the "CONTROL DEPENDENCIES" section of
+ Documentation/memory-barriers.txt for more details.
+
+ o The pointers are not equal -and- the compiler does
+ not have enough information to deduce the value of the
+ pointer. Note that the volatile cast in rcu_dereference()
+ will normally prevent the compiler from knowing too much.
+
+o Disable any value-speculation optimizations that your compiler
+ might provide, especially if you are making use of feedback-based
+ optimizations that take data collected from prior runs. Such
+ value-speculation optimizations reorder operations by design.
+
+ There is one exception to this rule: Value-speculation
+ optimizations that leverage the branch-prediction hardware are
+ safe on strongly ordered systems (such as x86), but not on weakly
+ ordered systems (such as ARM or Power). Choose your compiler
+ command-line options wisely!
+
+
+EXAMPLE OF AMPLIFIED RCU-USAGE BUG
+
+Because updaters can run concurrently with RCU readers, RCU readers can
+see stale and/or inconsistent values. If RCU readers need fresh or
+consistent values, which they sometimes do, they need to take proper
+precautions. To see this, consider the following code fragment:
+
+ struct foo {
+ int a;
+ int b;
+ int c;
+ };
+ struct foo *gp1;
+ struct foo *gp2;
+
+ void updater(void)
+ {
+ struct foo *p;
+
+ p = kmalloc(...);
+ if (p == NULL)
+ deal_with_it();
+ p->a = 42; /* Each field in its own cache line. */
+ p->b = 43;
+ p->c = 44;
+ rcu_assign_pointer(gp1, p);
+ p->b = 143;
+ p->c = 144;
+ rcu_assign_pointer(gp2, p);
+ }
+
+ void reader(void)
+ {
+ struct foo *p;
+ struct foo *q;
+ int r1, r2;
+
+ p = rcu_dereference(gp2);
+ if (p == NULL)
+ return;
+ r1 = p->b; /* Guaranteed to get 143. */
+ q = rcu_dereference(gp1); /* Guaranteed non-NULL. */
+ if (p == q) {
+ /* The compiler decides that q->c is same as p->c. */
+ r2 = p->c; /* Could get 44 on weakly order system. */
+ }
+ do_something_with(r1, r2);
+ }
+
+You might be surprised that the outcome (r1 == 143 && r2 == 44) is possible,
+but you should not be. After all, the updater might have been invoked
+a second time between the time reader() loaded into "r1" and the time
+that it loaded into "r2". The fact that this same result can occur due
+to some reordering from the compiler and CPUs is beside the point.
+
+But suppose that the reader needs a consistent view?
+
+Then one approach is to use locking, for example, as follows:
+
+ struct foo {
+ int a;
+ int b;
+ int c;
+ spinlock_t lock;
+ };
+ struct foo *gp1;
+ struct foo *gp2;
+
+ void updater(void)
+ {
+ struct foo *p;
+
+ p = kmalloc(...);
+ if (p == NULL)
+ deal_with_it();
+ spin_lock(&p->lock);
+ p->a = 42; /* Each field in its own cache line. */
+ p->b = 43;
+ p->c = 44;
+ spin_unlock(&p->lock);
+ rcu_assign_pointer(gp1, p);
+ spin_lock(&p->lock);
+ p->b = 143;
+ p->c = 144;
+ spin_unlock(&p->lock);
+ rcu_assign_pointer(gp2, p);
+ }
+
+ void reader(void)
+ {
+ struct foo *p;
+ struct foo *q;
+ int r1, r2;
+
+ p = rcu_dereference(gp2);
+ if (p == NULL)
+ return;
+ spin_lock(&p->lock);
+ r1 = p->b; /* Guaranteed to get 143. */
+ q = rcu_dereference(gp1); /* Guaranteed non-NULL. */
+ if (p == q) {
+ /* The compiler decides that q->c is same as p->c. */
+ r2 = p->c; /* Locking guarantees r2 == 144. */
+ }
+ spin_unlock(&p->lock);
+ do_something_with(r1, r2);
+ }
+
+As always, use the right tool for the job!
+
+
+EXAMPLE WHERE THE COMPILER KNOWS TOO MUCH
+
+If a pointer obtained from rcu_dereference() compares not-equal to some
+other pointer, the compiler normally has no clue what the value of the
+first pointer might be. This lack of knowledge prevents the compiler
+from carrying out optimizations that otherwise might destroy the ordering
+guarantees that RCU depends on. And the volatile cast in rcu_dereference()
+should prevent the compiler from guessing the value.
+
+But without rcu_dereference(), the compiler knows more than you might
+expect. Consider the following code fragment:
+
+ struct foo {
+ int a;
+ int b;
+ };
+ static struct foo variable1;
+ static struct foo variable2;
+ static struct foo *gp = &variable1;
+
+ void updater(void)
+ {
+ initialize_foo(&variable2);
+ rcu_assign_pointer(gp, &variable2);
+ /*
+ * The above is the only store to gp in this translation unit,
+ * and the address of gp is not exported in any way.
+ */
+ }
+
+ int reader(void)
+ {
+ struct foo *p;
+
+ p = gp;
+ barrier();
+ if (p == &variable1)
+ return p->a; /* Must be variable1.a. */
+ else
+ return p->b; /* Must be variable2.b. */
+ }
+
+Because the compiler can see all stores to "gp", it knows that the only
+possible values of "gp" are "variable1" on the one hand and "variable2"
+on the other. The comparison in reader() therefore tells the compiler
+the exact value of "p" even in the not-equals case. This allows the
+compiler to make the return values independent of the load from "gp",
+in turn destroying the ordering between this load and the loads of the
+return values. This can result in "p->b" returning pre-initialization
+garbage values.
+
+In short, rcu_dereference() is -not- optional when you are going to
+dereference the resulting pointer.