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authorJonathan Brassow <jbrassow@redhat.com>2013-02-21 03:28:10 +0100
committerNeilBrown <neilb@suse.de>2013-02-26 01:55:30 +0100
commit475901aff15841fb0a81e7546517407779a9b061 (patch)
tree22a641d5ff0f86db53cba49f6f701b16e9148507 /drivers/md/raid10.h
parentMD RAID10: Minor non-functional code changes (diff)
downloadlinux-475901aff15841fb0a81e7546517407779a9b061.tar.xz
linux-475901aff15841fb0a81e7546517407779a9b061.zip
MD RAID10: Improve redundancy for 'far' and 'offset' algorithms (part 1)
The MD RAID10 'far' and 'offset' algorithms make copies of entire stripe widths - copying them to a different location on the same devices after shifting the stripe. An example layout of each follows below: "far" algorithm dev1 dev2 dev3 dev4 dev5 dev6 ==== ==== ==== ==== ==== ==== A B C D E F G H I J K L ... F A B C D E --> Copy of stripe0, but shifted by 1 L G H I J K ... "offset" algorithm dev1 dev2 dev3 dev4 dev5 dev6 ==== ==== ==== ==== ==== ==== A B C D E F F A B C D E --> Copy of stripe0, but shifted by 1 G H I J K L L G H I J K ... Redundancy for these algorithms is gained by shifting the copied stripes one device to the right. This patch proposes that array be divided into sets of adjacent devices and when the stripe copies are shifted, they wrap on set boundaries rather than the array size boundary. That is, for the purposes of shifting, the copies are confined to their sets within the array. The sets are 'near_copies * far_copies' in size. The above "far" algorithm example would change to: "far" algorithm dev1 dev2 dev3 dev4 dev5 dev6 ==== ==== ==== ==== ==== ==== A B C D E F G H I J K L ... B A D C F E --> Copy of stripe0, shifted 1, 2-dev sets H G J I L K Dev sets are 1-2, 3-4, 5-6 ... This has the affect of improving the redundancy of the array. We can always sustain at least one failure, but sometimes more than one can be handled. In the first examples, the pairs of devices that CANNOT fail together are: (1,2) (2,3) (3,4) (4,5) (5,6) (1, 6) [40% of possible pairs] In the example where the copies are confined to sets, the pairs of devices that cannot fail together are: (1,2) (3,4) (5,6) [20% of possible pairs] We cannot simply replace the old algorithms, so the 17th bit of the 'layout' variable is used to indicate whether we use the old or new method of computing the shift. (This is similar to the way the 16th bit indicates whether the "far" algorithm or the "offset" algorithm is being used.) This patch only handles the cases where the number of total raid disks is a multiple of 'far_copies'. A follow-on patch addresses the condition where this is not true. Signed-off-by: Jonathan Brassow <jbrassow@redhat.com> Signed-off-by: NeilBrown <neilb@suse.de>
Diffstat (limited to 'drivers/md/raid10.h')
-rw-r--r--drivers/md/raid10.h5
1 files changed, 5 insertions, 0 deletions
diff --git a/drivers/md/raid10.h b/drivers/md/raid10.h
index 1054cf602345..157d69e83ff4 100644
--- a/drivers/md/raid10.h
+++ b/drivers/md/raid10.h
@@ -33,6 +33,11 @@ struct r10conf {
* far_offset, in which case it is
* 1 stripe.
*/
+ int far_set_size; /* The number of devices in a set,
+ * where a 'set' are devices that
+ * contain far/offset copies of
+ * each other.
+ */
int chunk_shift; /* shift from chunks to sectors */
sector_t chunk_mask;
} prev, geo;