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authorGustavo A. R. Silva <gustavo@embeddedor.com>2019-04-03 18:40:52 +0200
committerKalle Valo <kvalo@codeaurora.org>2019-04-25 18:45:14 +0200
commitae187ba915412d20de8a6470ebaa7670c4d1e1e5 (patch)
tree052c591a46360f43b4bebe81a9e409713eb0a650 /drivers/sfi
parentrsi: miscallaneous changes for 9116 and common (diff)
downloadlinux-ae187ba915412d20de8a6470ebaa7670c4d1e1e5.tar.xz
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mwifiex: use struct_size() in kzalloc()
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; struct boo entry[]; }; size = sizeof(struct foo) + count * sizeof(struct boo); instance = kzalloc(size, GFP_KERNEL) Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL) Notice that, in this case, variable regd_size is not necessary, hence it is removed. This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Signed-off-by: Kalle Valo <kvalo@codeaurora.org>
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