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authorGustavo A. R. Silva <gustavoars@kernel.org>2020-05-24 22:52:38 +0200
committerPaul Moore <paul@paul-moore.com>2020-06-17 22:43:11 +0200
commitbbccc11bc8848926065915e6193fd4c6e33c85ef (patch)
tree87c2225344fc30b92dd8035e1ad10947359f7545 /kernel/audit_tree.c
parentLinux 5.8-rc1 (diff)
downloadlinux-bbccc11bc8848926065915e6193fd4c6e33c85ef.tar.xz
linux-bbccc11bc8848926065915e6193fd4c6e33c85ef.zip
audit: Use struct_size() helper in alloc_chunk
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct audit_chunk { ... struct node { struct list_head list; struct audit_tree *owner; unsigned index; /* index; upper bit indicates 'will prune' */ } owners[]; }; Make use of the struct_size() helper instead of an open-coded version in order to avoid any potential type mistakes. So, replace the following form: offsetof(struct audit_chunk, owners) + count * sizeof(struct node); with: struct_size(chunk, owners, count) This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavoars@kernel.org> Signed-off-by: Paul Moore <paul@paul-moore.com>
Diffstat (limited to 'kernel/audit_tree.c')
-rw-r--r--kernel/audit_tree.c4
1 files changed, 1 insertions, 3 deletions
diff --git a/kernel/audit_tree.c b/kernel/audit_tree.c
index e49c912f862d..1b7a2f041793 100644
--- a/kernel/audit_tree.c
+++ b/kernel/audit_tree.c
@@ -188,11 +188,9 @@ static struct fsnotify_mark *alloc_mark(void)
static struct audit_chunk *alloc_chunk(int count)
{
struct audit_chunk *chunk;
- size_t size;
int i;
- size = offsetof(struct audit_chunk, owners) + count * sizeof(struct node);
- chunk = kzalloc(size, GFP_KERNEL);
+ chunk = kzalloc(struct_size(chunk, owners, count), GFP_KERNEL);
if (!chunk)
return NULL;